Please find the attachment of PF improvement Table.

Example: Supplying load of 650Kw at a PF of 0.65. What size of capacitors is required to raise the PF to unity(1)? And how many more KW can connect** **for the same kVA loading when P.F improved.

Supplying kW = 650 kW

Multiplier to improve PF from 0.65 to unity (1) is 1.169.

Required Capacitor kVAR = kW x Table 1 Multiplier of 65 and 100

= 650kW x 1.169

= 759.85 kVAR

We know that P.F = Cosθ = kW/kVA . . .or

kVA = kW / Cosθ

= 650/0.65 = 1000 kVA

When Power Factor is raised to unity (1)

No of kW = kVA x Cosθ

= 1000 x 1 = 1000kW

Hence increased Power supplied

1000kW – 650kW = 350kW

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